In the figure shown below masses of blocks A and B are 3 kg and 6 kg respectively. The force constants of springs S 1 and S 2 are 160 N/m and 40 N/m respectively. Length of the light string connecting the blocks is 8 m. The system is released from rest with the springs at their natural lengths. The maximum elongation of spring S 1 will be:
Text Solution
Verified by ExpertsThe correct answer is:
A
6g(x) – 3g(x) = 
6g = (k 1 + k 2 ) x
u 2 = 0.294m
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